Update Gram matrix parameterization

Glen Whitney 2025-02-19 20:39:46 +00:00
parent ae05a0f03a
commit 5c4d46cea8

@ -60,7 +60,7 @@ It follows that
d\mathcal{P}(X) & = \sum_{(i, j) \in \mathcal{C}} E_{ij}\,dX^\top E_{ij} \\ d\mathcal{P}(X) & = \sum_{(i, j) \in \mathcal{C}} E_{ij}\,dX^\top E_{ij} \\
& = \mathcal{P}(dX). & = \mathcal{P}(dX).
\end{align*} \end{align*}
\] ```
Since the subspace $C$ is transpose-invariant, we also have Since the subspace $C$ is transpose-invariant, we also have
\[ \mathcal{P}(X^\top) = \mathcal{P}(X)^\top. \] \[ \mathcal{P}(X^\top) = \mathcal{P}(X)^\top. \]
We can now see that We can now see that